5.1 For the purposes of this example, it is assumed
that calculations have been carried out for all the 8 groups of people
into which the evacuation is organized, according to the evacuation
procedure described in paragraph 3.3 above.
It is further assumed that the highest travel time is obtained for
the group of people moving (phase 1) from the afterward passenger
area in the upper deck down to MES 3 and 4 respectively on the lower
deck.
5.2 The schematization of the escape route is
shown in figure 4. As it may
be seen, the elements composing the escape path are 2 doors, 2 corridors
and 1 stairway.
5.3 The characteristics of the escape path's elements
are as follows:
|
Element
|
L (m)
|
Wc (m)
|
Fs
|
S (m/s)
|
Fc
(p/s)
|
N
people
|
| Door 1
|
N.A.
|
1.4
|
1.3
|
N.A.
|
1.82
|
165
|
| Corridor 1
|
14
|
4.2
|
1.3
|
0.67
|
5.46
|
165
|
| Stairway 1
|
4.7
|
3.5
|
1.1
|
0.55
|
3.85
|
165
|
| Corridor 2
|
14
|
3.0
|
1.3
|
0.67
|
3.90
|
200
|
| Door 2A
|
N.A
|
1.4
|
1.3
|
N.A.
|
1.82
|
100
|
| Door 2B
|
N.A
|
1.4
|
1.3
|
N.A.
|
1.82
|
100
|
The values of specific flow (Fs) and speed (S)
are taken from table 3.6 of
the guidelines; the value of calculated flow (Fc) is obtained
by Fc = Fs Wc (see paragraph 3.6.1.4 of the guidelines).
5.4 The resulting walking time (tw)
and flow time (tF), calculated according to paragraphs 3.6.1.5 and 3.6.1.6 of the
guidelines are as follows:
|
Element
|
L (m)
|
Wc (m)
|
N people
|
tw (s)
|
tF (s)
|
| Door 1
|
N.A.
|
1.4
|
165
|
N.A.
|
91
|
| Corridor 1
|
14
|
4.2
|
165
|
21
|
30
|
| Stairway 1
|
4.7
|
3.5
|
165
|
9
|
43
|
| Corridor 2
|
14
|
3.0
|
200
|
21
|
51
|
| Door 2A
|
N.A.
|
1.4
|
100
|
N.A.
|
55
|
| Door 2B
|
N.A.
|
1.4
|
100
|
N.A.
|
55
|
5.5 The resulting total walking time is the sum
of the walking time of each element in the escape path and totals
51 s. The flow time is the highest among all the elements in the escape
path and corresponds to 91 s. Accordingly, the ideal travel time is
where, tI = 142 s.
Figure 4 Sketch of the evacuation path and its schematization