3.1.1 To calculate the mTRL of a component, its original TRL must be
multiplied by its reduction factor (see
Ch 3, 2.10 Revision of technology assessment). The
reduction factor for a specific component is based upon the lowest IRL between all
other components it interacts with.
3.1.2 To derive the reduction factor for a specific component a sliding scale
is assumed for an IRL of 1 to 7. This is because the confidence level of an
individual component in a system is wholly dependent upon the quality of its
interaction with other components (i.e. the lower the IRL, the higher the reduction
factor).
3.1.3 In
Figure 5.3.1 Reduction factor for IRL 1
- 7, the
sliding scale assumes a reduction factor of IRL(1) = 50 per cent and IRL(7) = 100
per cent.
adopting the equation for
the slope of a line,
|
|
|
y = mx + c
|
(i)
|
from Figure 5.3.1 Reduction factor for IRL 1
- 7, we have:
|
|
|
1,0 = m(7) + c
|
(ii)
|
and
|
|
|
|
0,5 = m(1) +c
|
(iii)
|
performing simultaneous
equations for equations (ii) and (iii)
|
|
we have,
|
|
|
|
0,5 = 6m
|
(iv)
|
|
therefore, m = 0,083
|
(v)
|
substituting for ‘m’ in
equation (ii), we have,
|
|
|
1,0 = 0,083(7) +c
|
(vi)
|
|
therefore, c = 0,417
|
(vii)
|
Figure 5.3.1 Reduction factor for IRL 1
- 7
Hence, for example, the reduction factor
(y) for a component that has the
lowest IRL between interfacing components = 3, is given as:
y
= 0,083 (3) + 0,417
|
(viii)
|
therefore y = 0,67
|
(ix)
|