Section 3 Derivation of a reduction factor for a component
Clasification Society 2024 - Version 9.40
Clasifications Register Guidance Information - Guidance Notes for Certification through Technology Qualification, January 2022 - Chapter 5 Appendices - Section 3 Derivation of a reduction factor for a component

Section 3 Derivation of a reduction factor for a component

3.1 Derivation of component's reduction factor

3.1.1 To calculate the mTRL of a component, its original TRL must be multiplied by its reduction factor (see Ch 3, 2.10 Revision of technology assessment). The reduction factor for a specific component is based upon the lowest IRL between all other components it interacts with.

3.1.2 To derive the reduction factor for a specific component a sliding scale is assumed for an IRL of 1 to 7. This is because the confidence level of an individual component in a system is wholly dependent upon the quality of its interaction with other components (i.e. the lower the IRL, the higher the reduction factor).

3.1.3 In Figure 5.3.1 Reduction factor for IRL 1 - 7, the sliding scale assumes a reduction factor of IRL(1) = 50 per cent and IRL(7) = 100 per cent.
adopting the equation for the slope of a line,  
  y = mx + c (i)
from Figure 5.3.1 Reduction factor for IRL 1 - 7, we have:  
  1,0 = m(7) + c (ii)
and    
  0,5 = m(1) +c (iii)
performing simultaneous equations for equations (ii) and (iii)  
we have,    
  0,5 = 6m (iv)
  therefore, m = 0,083 (v)
substituting for ‘m’ in equation (ii), we have,  
  1,0 = 0,083(7) +c (vi)
  therefore, c = 0,417 (vii)

Figure 5.3.1 Reduction factor for IRL 1 - 7

Hence, for example, the reduction factor (y) for a component that has the lowest IRL between interfacing components = 3, is given as:
y = 0,083 (3) + 0,417 (viii)
therefore y = 0,67 (ix)

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