I Combined transverse, horizontal and longitudinal subdivision
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Statutory Documents - IMO Publications and Documents - Resolutions - Assembly - IMO Resolution A.684(17) – Explanatory Notes to the Solas Regulations on Subdivision and Damage Stability of Cargo Ships of 100 Metres In Length and Over – (Adopted on 6 November 1991) - Annex - Explanatory Notes to the SOLAS Regulations on Subdivision and Damage Stability of Cargo Ships of 100 Metres in Length and Over - Appendix 2 - I Combined transverse, horizontal and longitudinal subdivision

I Combined transverse, horizontal and longitudinal subdivision

  1 Provision has been included in the new regulations to permit evaluation and acceptance of ships with combined longitudinal and transverse subdivision. To facilitate a full understanding and correct and uniform application of the new provisions, some illustrative material is contained in this appendix. The examples given are based on three different arrangements of combined longitudinal and transverse subdivision as shown in figures A-3, A-4 and A-5.

Figure A-3 Illustration of combined damage at the end of undamaged centre compartment

figure A-4 Combined longitudinal and transverse subdivision - Arrangement example 1

Figure A-5 Combined longitudinal and transverse subdivision - Arrangement example 2

  2 The following nomenclature is used in this section:

l 1,l 2,l 3, etc. distance between bulkheads bounding either inboard or wing compartments as shown in figures A-3, A-4 and A-5;
l 12 = l 1 + l 2; l 23 = l 2+ l 3; l 34 = l 3 + l 4, etc.  
l 1-3 = l 1 + l 2 + l 3; l 2-4 = l 2 + l 3 + l 4,  
l 2-5 = l 2 + l 3 + l 4 + l 5; l 3-6 = l 3 + l 4 + l 5 + l 6, etc.;  
p 1, p2, p3, etc. are p calculated according to regulation 25-5.1 using l 1, l 2, l 3, etc. as l;
p 12, p23, p34, etc. are p calculated according to regulation 25-5.1 using l 12, l 23, l 34, etc. as l;
p 1-3, p2-4, etc. are p calculated according to regulation 25-5.1 using l 1-3, l 2-4, etc. as l;
p 2-5, p3-6, etc. are p calculated according to regulation 25-5.1 using l 2-5, l 3-6, etc. as l;
r 1, r 2, r 3, etc. are r calculated according to regulation 25-5.2 using l 1, l 2, l 3, etc. as l, and b as defined in regulation 25-5.2;
r 12, r 23, r 34, etc. are r calculated according to regulation 25-5.2 using l 12, l 23, l 34, etc. as l, and b as defined in regulation 25-5.2;
r 2-5, r 3-6, etc. are r calculated according to regulation 25-5.2 using l 2-5, l 3-6, etc. as l, and b as defined in regulation 25-5.2;
b as defined in regulation 25-5.2;

 In calculating r-values for a group of two or more adjacent compartments, the b-value is common for all compartments in that group, and equal to the smallest b-value in that group:

where:
n = number of wing compartments in that group;

b 1, b 2 … b n are the mean values of b for individual wing compartments contained in the group.

 When determining the factor p for simultaneous flooding of space 1 (in Figures A-4 and A-5) and adjacent side compartment(s) the values r 1, r 12, etc., should be calculated according to Regulation 25-5.2, taking b for space 1 equal to the breadth of the adjacent side compartment(s).

Table A-3 Application of regulation 25-5 to subdivision arrangement shown in figure A-4

Damage zone(s) as compartment or group of compartmentsfootnote p-factor Distances X 1 and X 2 for determination of factor p
1 p = p 1 X 1 = 0 X 2 = l 1
W 2,3 p = p 23 x r 23 X 1 = l 1 X 2 = l 1-3
W 4,5 p = p 45 x r 45 X 1 = l 1-3 X 2 = l 1-5
1 and W 2,3 p = p 1-3 x r 1-3 - p 1 x r 1 - p 23 x r 23 X 1 = 0 X 2 = l 1-3
W 2,3 and W 4,5 p = p 2-5 x r 2-5 - p 23 x r 23 - p 45 - r 45 X 1 = l 1 X 2 = l 1-5
1 and W 2,3 and W 4,5 p = p 1-5 x r 1-5 - p 1-3 x r 1-3 - p 2-5 x r 2-5 + p 23 x r 23 X 1 = 0 X 2 = l 1-5
W 2,3 and W 4,5 and W 6,7 p = p 2-7 x r 2-7 - p 2-5 x r 2-5 - p 4-7 x r 4=7 + p 45 x r 45 X 1 = l 1 X 2 = l 1-7

  .r 1-5 is a function of l 1-5 and b 2-5.

  .r 45 is a function of l 45 and b 2-7.

Table A-4 Application of regulation 25-5 to subdivision arrangement shown in figure A-4

Damage zone(s) as compartment or group of compartmentsfootnote p-factor Distances X 1 and X 2for determination of factor p
C 2 and W 2,3 p = p 2 x (1-r 2) X 1 = l 1 X 2 = l 12
C 3 and W 2,3 p = p 3 x (1-r 3) X 1 = l 12 X 2 = l 1-3
C 4 and W 4,5 p = p 4 x (1-r 4) X 1 = l 1-3 X 2 = l 1-4
1 and C 2 and W 2,3 p = p 12(1-r 12) - p 1(1-r 1) - p 2(1-r 2) X 1 = 0 X 2 = l 12
C 2 and C 3 and W 2,3 p = p 23(1-r 23) - p 2(1-r 2) - p 3(1-r 3) X 1 = l 1 X 2 = l 1-3
C 3 and C 4 and W 2,3 and W 4,5 p = p 34(1-r 34) - p 3(1-r 3) - p 4(1-r 4) X 1 = l 12 X 2 = l 1-4
1 and C 2 and C 3 and W 2,3 p = p 1-3(1-r 1-3) - p 12(1-r 12) - p 23(1-r 23) + p 2(1-r 2) X 1 = 0 X 2 = l 1-3
C 2 and C 3 and C 4 and W 2,3 and W,4,5 p = p 2-4(1-r 2-4) - p 23(1-r 23) - p 34(1-r 34) + p 3(1-r 3) X 1 = l 1 X 2 = l 1-4

Table A-5 Application of regulation 25-5 to subdivision arrangement shown in figure A-5

Damage zone(s) as compartment or group of compartmentsfootnote p-factor Distances X 1 and X 2for determination of factor p
1 p = p 1 X 1 eq 0 X 2 eq l 1
W 2 p = p 2 x r 2 X 1 = l 1 X 2 = l 12
W 3,4 p = p 34 x r 34 X 1 = l 12 X 2 = l 1-4
1 and W 2 p = p 12 x r 12 - p 1 x r 1 - p 2 x r 2 X 1 = 0 X 2 = l 12
W 2 and W 3,4 p = p 2-4 x r 2-4 - p 2 x r 2 - p 34 x r 34 X 1 = l 1 X 2 = l 1-4
1 and W 2 and W 3,4 p = p 1-4 x r 1-4 - p 12 x r 12 - p 2-4 x r 2-4 + p 2 x r 2 X 1 = 0 X 2 = l 1-4
W 2 and W 3,4 and W 5,6 p = p 2-6 x r 2-6 - p 2-4 x r 2-4 - p 3-6 x r 3-6 + p 34 x r 34 X 1 = l 1 X 2 = l 1-6

Table A-6 Application of regulation 25-5 to subdivision arrangement shown in figure A-

Damage zone(s) as compartment or group of compartmentsfootnote p-factor Distances X 1 and X 2for determination of factor p
C 2,3 and W 2 p = p 2(1-r 2) X 1 = l 1 X 2 = l 12
C 2,3 and W 3,4 p = p 3(1-r 3) X 1 = l 12 X 2 = l 1-3
C 4,5 and W 3,4 p = p 4(1-r 4) X 1 = l 1-3 X 2 = l 1-4
1 and C 2,3 and W 2 p = p 12(1-r 12) - p 1(1-r 1) - p 2(1-r 2) X 1 = 0 X 2 = l 12
1 and C 2,3 and W 2 and W 3,4 p = p 1-3(1-r 1=3) - p 2(1-r 12) - p 23(1-r 23) + p 2(1-r 2) X 1 = 0 X 2 = l 1-3
C 2,3 and C 4,5 and W 3,4 p = p 34(1-r 34) X 1 = l 12 X 2 = l 1-4
C 2,3 and C 4,5 and W 2 and W 3,4 p = p 24(1-r 24) - p 2(1-r 2) - p 34(1-r 34) X 1 = l 1 X 2 = l 1-4
C 2,3 and C 4,5 and W 3,4 and W 5,6 p = p 35(1-r 35) - p 34(1-r 34) - p 5(1-r 5 X 1 = l 12 X 1 = l 1-5
C 2,3 and C 4,5 and W 2 and W 3,4 and W 5,6 p = p 25(1-r 25) - p 24(1-r 24) - p 35(1-r 35 + p 34(1-r 34) X 1 = l 1 X 2 = l 1-5
Parent topic: Appendix 2
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